Asked by Nma odim
Two boats A and B leave port P at the same time. Boat A sails 30km in the North east direction and boat B sails 20km on a bearing of 300 degrees. What is the distance between the two boats and what is the bearing of boat A from boat B
Answers
Answered by
mathhelper
Why are you using two different directional notations?
I will convert them to standard trig notation.
NE ----> 45°
"bearing" of 300 ---> 150°
angle between the two arms = 105° (make a sketch to see)
now if the distance between them is d , then
d^2 = 20^2 + 30^2 - 2(20)(30)cos105
= 1300 - 1200(-.25882)
d = approx 40.13
find one of the other angles using the Sine Law, and you can then
find all the angles in your sketch
I will convert them to standard trig notation.
NE ----> 45°
"bearing" of 300 ---> 150°
angle between the two arms = 105° (make a sketch to see)
now if the distance between them is d , then
d^2 = 20^2 + 30^2 - 2(20)(30)cos105
= 1300 - 1200(-.25882)
d = approx 40.13
find one of the other angles using the Sine Law, and you can then
find all the angles in your sketch
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