Asked by adeola

two boats a and left a port c at the same time on different route b travelled on a bearing of 150 and a travelled on the north side of b when a had travelled 8km and b travelled 10km the distance between the two boats was found to be 12km calculate the bearing of route a from c
Answered by Reiny
Let me repost your question in proper English:

Two boats A and B left a port C at the same time on different routes. B travelled on a bearing of 150° and A travelled on the north side of B. When A had travelled 8 km and B travelled 10 km, the distance between the two boats was found to be 12 km. Calculate the bearing of the route A from C.

Start by sketching line CB for which you are given the distance and direction.
Complete triangle ABC. You now have a triangle with all 3 sides given.
We can find angle C using the Cosine Law.
12^2 = 8^2 + 10^2 - 2(8)(10)cos C
160cos C = 64 + 100 - 144
cos C = 1/8

Find angle C, and then you can state the bearing using the original direction of 150°
Answered by Damon
Traveled on a HEADING !
If I look at the lighthouse through a hand bearing compass, that is a "bearing".
If I steer a compass course, that is a "heading".

The second use of "bearing" is correct:
"Calculate the bearing of the route A from C."

( math talk drives me crazy)
Answered by Damon
Actually bearing of BOAT A from C ( which is the heading of A if there is no wind or current.)
Answered by Moyosore
The question is a little bit complicated
Have tried my best but cant get it
Someone should kindly please give me some hints 🙃🙃😔😔😪😪
Answered by Moyosore
Two boats A and B left a port C at the same time on different routes. B travelled on a bearing of 150° and A travelled on the north side of B. When A had travelled 8 km and B travelled 10 km, the distance between the two boats was found to be 12 km. Calculate the bearing of the route A from C.? Hints needed pls?
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