Ask a New Question

Asked by Bee

DE bisects BC. If BC = 5x - 3 and CE = 2x + 25, find the value of x
4 years ago

Answers

Answered by desi
u should use mathway.com and symbolab.com. great for using them as quick calulators for any math problem
4 years ago
Answered by oobleck
5x-3 = 2(2x+25)
4 years ago
There are no AI answers yet. The ability to request AI answers is coming soon!

Submit Your Answer


We prioritize human answers over AI answers.

If you are human, and you can answer this question, please submit your answer.

Related Questions

ray OC bisects <AOB, ray OD bisects <AOC, RAY OE BISECTS <AOD, RAY OF BISECTS <AOE NAD RAY OG BISECT... -> OB bisects <AOC m<AOB=6x, m<AOC=2x+2y, m<BOC=y+5 Given: ray AD bisects <BAC <DAC=3x, and <BAD=5x-24 Prove: x=12 its a proof and i need help --> BD bisects <adc, m<1=5x-3, and m<2=x+25. find the value of X gk bisects <fgh if m<fgk=7w+3 and m<fgh=104, find w Given: QS bisects ∠RQT; ∠R ≅ ∠ T Prove: SQ bisects ∠RST /Users/szeringue/Documents/triangle.doc 1. MO bisects LMN, LMN = 5x-23, LMO = x+32. Find NMO. >>I got the answer 45.75 but I got it wrong.... MO bisects <LMN,m<NMO=(6x+19)°,andm<LMO=(9x-14)°. Solve for x and find <LMN. Given --->VY bisects <TVZ. --->ZY bisects <TZV. <TVZ =~ <TZV Conclusion: <3 =~ <1 Given: FG (SEG) bisects BT (SEG) BO=7x-6 OT=5x+10 Prove: BO=5...
Submit Your Answer

Question

DE bisects BC. If BC = 5x - 3 and CE = 2x + 25, find the value of x

Ask a New Question
Archives Contact Us Privacy Policy Terms of Use