MO bisects <LMN,m<NMO=(6x+19)°,andm<LMO=(9x-14)°. Solve for x and find <LMN.

Answer 1

So the two angles would have to be equal

9x - 14 = 6x + 19
3x = 33
x = 11

angle LMO = 9x-14 = 99-14 = 85°

then angle LMN = 2*85 = 170°

Answer 2

Lm=5x-1. Kl=3x+2

Answer 3

i dont know sooooo