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Given: FG (SEG) bisects BT (SEG)

BO=7x-6
OT=5x+10

Prove: BO=50

2 answers

There appears to be insufficient information. Where is O, with respect to BT and FG?

It appears to me that O is midway between B and T. If so, then

7x-6 = 5x+10
2x = 16
x = 8

So, BO = 5*8+10 = 50

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