Asked by Elliot
Aluminum oxide is formed when aluminum combines with oxygen in the air. How many grams of Al2O3 are formed when 13.6 mol of Al reacts?
4 Al + 3 O2 → 2 Al2O3
4 Al + 3 O2 → 2 Al2O3
Answers
Answered by
Anonymous
2/4 = 1/2 so half as many mols
13.6 / 2 = 6.8 mols of Al2O3
Al2O3 = 2*27+3*16 = 102 grams/mol
6.8 * 102 = ?
13.6 / 2 = 6.8 mols of Al2O3
Al2O3 = 2*27+3*16 = 102 grams/mol
6.8 * 102 = ?
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.