Question
Aluminum oxide is formed when aluminum combines with oxygen in the air. How many grams of Al2O3 are formed when 13.6 mol of Al reacts?
4 Al + 3 O2 → 2 Al2O3
4 Al + 3 O2 → 2 Al2O3
Answers
Anonymous
2/4 = 1/2 so half as many mols
13.6 / 2 = 6.8 mols of Al2O3
Al2O3 = 2*27+3*16 = 102 grams/mol
6.8 * 102 = ?
13.6 / 2 = 6.8 mols of Al2O3
Al2O3 = 2*27+3*16 = 102 grams/mol
6.8 * 102 = ?