Asked by meg
Iron(III) oxide is formed when iron combines with oxygen in the air. How many grams of Fe2O3 are formed when 16.7 g of Fe reacts completely with oxygen?
Answers
Answered by
DrBob222
1. Write and balance the equation.
4Fe + 3O2 ==> 2Fe2O3
2. Convert what you have (in this case 16.7 g Fe) to moles. moles = grams/molar mass.
3. Using the coefficients in the balanced equation, convert moles of what you have (Fe) to moles of what you want (in this case Fe2O3).
4. Now convert moles of Fe2O3 to grams.
g = moles Fe2O3 x molar mass Fe2O3.
4Fe + 3O2 ==> 2Fe2O3
2. Convert what you have (in this case 16.7 g Fe) to moles. moles = grams/molar mass.
3. Using the coefficients in the balanced equation, convert moles of what you have (Fe) to moles of what you want (in this case Fe2O3).
4. Now convert moles of Fe2O3 to grams.
g = moles Fe2O3 x molar mass Fe2O3.
Answered by
meg
I STILL HAVE NO IDEA!!!
Answered by
DrBob222
You've got to be kidding. Just follow the instructions.
Answered by
Jessica
23.9 g its not that hard buddy
Answered by
ellie
.... this conversation aged well i see fancy meeting you guys here
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