Asked by John
Use trig identities to transform the expression (sec θ)/(csc θ) into a single trig function. Assume θ is acute. Work must be shown for credit.
Answers
Answered by
mathhelper
(sec θ)/(csc θ)
= (1/cos θ)(1/sin θ) , but we know sin 2A = 2sinAcosA
= 1/(sinθcosθ)
= 2/sin(2θ)
= (1/cos θ)(1/sin θ) , but we know sin 2A = 2sinAcosA
= 1/(sinθcosθ)
= 2/sin(2θ)
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