Ask a New Question

Question

Two ships leave a harbor together, traveling on courses that have an angle of 135° between them. If one ship travels 402 miles and the other ship travels 500 miles, how far apart are the ships? __________

What is the area of water between the ships and the harbor? ____________
4 years ago

Answers

oobleck
use the law of cosines to find the distance: c^2 = a^2+b^2-2ab cosC
Then the area is 1/2 ab sinC
4 years ago

Related Questions

Two ships leave a harbor together traveling on courses that have an angle of 124° between them. If t... Two ships leave a harbor at the same time, traveling on courses that have an angle of 140 degrees... Ships A and B leave port together. For the next two hours, ship A travels at 30.0 in a direction 75... Two ships leave a harbor entrance at the same time. The first ship is traveling at a constant 10 mil... Two ships leave from the same port. One ship travels on a bearing of 157 degrees at 20 knots. The se... Two ships leave a harbor at the same time. One ship travels on a bearing S11 degrees W at 12 mph. Th... Two ships leave a harbor at the same time. One ship travels on a bearing s11w at 16 miles per hour.... two ships leave the same port at noon ship a sales north at 10 mph and ship B sales east of 20 mph.... Two ships leave a harbor at the same time. One ship travels on a bearing 15at 18 miles per hourThe o... Two ships leave a harbor at the same timeOne ship travels on a bearing s * 14 deg * w at 15 miles pe...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use