Question
Two ships leave a harbor entrance at the same time. The first ship is traveling at a constant 10 miles per hour, while the second is traveling at a constant 22 miles per hour. If the angle between their courses is 100°, how far apart are they after 2 hours? (Round your answer to the nearest whole number.)
Answers
recall the law of cosines. The distance z will be
z^2 = 20^2 + 44^2 - 2*20*44*cos100°
z^2 = 20^2 + 44^2 - 2*20*44*cos100°
Billy plus billy equals Tim, but since dong dong minus butthole equals marijuana the distance between Egor and Tryrone is 35 degrees minus the turd from marijuanas bong, so if 70 degrees is between Egor and his mom then 2,234.69 bong rips is how many it takes to get to the center of a tootsie pop.
Related Questions
Two ships leave a harbor at the same time, traveling on courses that have an angle of 140 degrees...
Two cargo ships are siling a direct course into harbor. Ship A is 22 miles from harbor. Ship B is sa...
Two ships leave a harbor together, traveling on courses that have an angle of 135° between them. If...