Asked by Pcwest
Two ships leave the same port at 7.am. The first ship sails towards europe on a 54 degree course at a constant rate of 36 mi/h. The second ship,neither a tropical destination, sails on a 144 degree course at a constant speed of 42 mi/h. Find the distance between the ships at 11. Am.
Answers
Answered by
Maddi
I hope this helps anyone.
11-7=4
36x4=144
42x4=168
Draw a triangle with an angle of 54 degrees. Then include the 54 degree angle in the 144 degree angle. Hope this makes sense.
Angle 144 overlaps angle 54.
144-54=90
So the angle of the distance between the ships is 90.
Then use the law of cosines
a^2=b^2+c^2-2bc(cosA)
a^2=144^2+168^2-2(144)(168)cos(90)
a^2=48960
a=√48960=221.27 miles
the final answer is 221.27 miles
11-7=4
36x4=144
42x4=168
Draw a triangle with an angle of 54 degrees. Then include the 54 degree angle in the 144 degree angle. Hope this makes sense.
Angle 144 overlaps angle 54.
144-54=90
So the angle of the distance between the ships is 90.
Then use the law of cosines
a^2=b^2+c^2-2bc(cosA)
a^2=144^2+168^2-2(144)(168)cos(90)
a^2=48960
a=√48960=221.27 miles
the final answer is 221.27 miles
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.