Question
Two ships P and Q leave a port R at the same time for their anchoring point. Both ship took 2 hours to reach their respective point with ship P sailing at 12 km/hr on a bearing of 280 ° and ship Q sailing at 10km/he on a bearing 030° (B) another ship S has an anchoring point such that it forms a straight line with ship P and Q i, calculate the bearing at Which ship S Should travel such that the distance from R to S is the minimum. ii, hence. Calculate this distance RS
Answers
RS is the altitude from PQ to R
PQ has length 41.37 and its direction is 81.9°
Using the law of sines,
sinP/20 = sin110°/41.37
P = 27°
RS /24 = sin27°
RS = 10.9
PQ has length 41.37 and its direction is 81.9°
Using the law of sines,
sinP/20 = sin110°/41.37
P = 27°
RS /24 = sin27°
RS = 10.9
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