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28. If x and y are natural numbers, find the number pairs (x, y) for which x^2 - y^2 = 31.
4 years ago

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oobleck
well, (n+1)^2 - n^2 = 2n+1, so one pair will be when n=15, so
16^2 - 15^2 = 256-225 = 31
think of (n+3)^2 - n^2
and so on.
(why not possible for (n+2)^2 - n^2 ?)
4 years ago
Anonymous
pata nahi
2 years ago

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