well 24 = 1*24 of course
24 = 2*12 = 2*3*4 = 2*2*2*3
2 2 2 3
2 2 6
2 4 3
2 12
3 8
so I have 1 2 3 4 6 8 12 24
a. {2 ,4, 6, 12}
b. {2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24}
c. {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24}
d. {1, 2, 3, 4, 6, 8, 12, 24}
24 = 2*12 = 2*3*4 = 2*2*2*3
2 2 2 3
2 2 6
2 4 3
2 12
3 8
so I have 1 2 3 4 6 8 12 24
We can start by listing the numbers from 1 to 24 and checking if each number divides 24 evenly.
1 ÷ 24 = 24 (remainder 0)
2 ÷ 24 = 12 (remainder 0)
3 ÷ 24 = 8 (remainder 0)
4 ÷ 24 = 6 (remainder 0)
5 ÷ 24 = 4 (remainder 4)
6 ÷ 24 = 4 (remainder 0)
7 ÷ 24 = 3 (remainder 3)
8 ÷ 24 = 3 (remainder 0)
9 ÷ 24 = 2 (remainder 2)
10 ÷ 24 = 2 (remainder 0)
11 ÷ 24 = 2 (remainder 2)
12 ÷ 24 = 2 (remainder 0)
13 ÷ 24 = 1 (remainder 13)
14 ÷ 24 = 1 (remainder 14)
15 ÷ 24 = 1 (remainder 15)
16 ÷ 24 = 1 (remainder 16)
17 ÷ 24 = 0 (remainder 17)
18 ÷ 24 = 0 (remainder 18)
19 ÷ 24 = 0 (remainder 19)
20 ÷ 24 = 0 (remainder 20)
21 ÷ 24 = 0 (remainder 21)
22 ÷ 24 = 0 (remainder 22)
23 ÷ 24 = 0 (remainder 23)
24 ÷ 24 = 1 (remainder 0)
From this list, we can see that the numbers 1, 2, 3, 4, 6, 8, 12, and 24 divide evenly into 24 without leaving a remainder. Therefore, the set of natural numbers that are factors of 24 in roster form is {1, 2, 3, 4, 6, 8, 12, 24}.
So, the correct option is d. {1, 2, 3, 4, 6, 8, 12, 24}.