Asked by satyajit
If a and b are two natural numbers such that (a)^b =36 , then find the value of (b)^a-2.
Answers
Answered by
Anonymous
Let a=6 and b=2.
a^b=36 ------> 6^2=36
b^a-2 ---> 2^6-2 = 2^4=16
a^b=36 ------> 6^2=36
b^a-2 ---> 2^6-2 = 2^4=16
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