Question

Rays AB and BC are perpendicular. Point D lies in the interior of angle ABC. If m angle ABD = 3r+5 and m angle DBC= 5r-27, find m angle ABD ana m angle DBC.

Answer 1

ABD+DBC = ABC so
3r+5 + 5r-27 = 90
r = 14
Now finish it off

Answer 2

Hsgf

Answer 3

(3r+5) + (5r-27) = 90
8r - 22 = 90
8r = 112
8r/8 = 112/8
r = 14

<DBC = 5(14) - 27
<DBC = 43

Answer 4

(3r+5)+(5r-27)=90 8r-22=90 8r=90+22 8r÷8=112 ÷8 r=14. ABD= 3r+5 ABD=3(14)+5 ABD=42+5 ABD=47. DBC =5r-27 DBC=5(14)-27 DBC=70-27 DBC=43. The end!

Answer 5

WX and YZ intersect at point V. If mZWVY = (40 + 58)° and m/XVY = (26 - 18)°, find the values of a and b such that WX is perpendicular to YZ.