Asked by Monique N.

Rays PQ and QR are perpendicular. p;oint S lies in the interior of angle PQR. If angle PQS equals 4+7a and angle SQR equals 9+4a, find the angle PQS and angle SQR.


Can you please help me, I don't understand it.
Answered by Reiny
the two angles must add up to 90º

so solve 4+7a + 9+4a = 90

(I got the two angles to be 53 and 37 degrees)
Answered by Monique N.
how do you solve the equation tho. I don't understand how to do that part. I got the answer i just don't know how to solve the equation.
Answered by Reiny
4+7a + 9+4a = 90
11a = 90 - 4 - 9
11a = 77
a = 7

if a = 7, then 4+7a = 4+7(7) = 53
and 9+4a = 9 + 4(7) = 37
Answered by Monique N.
Thank you SOOOOOOOOOOOOOOOO much i really appreciate it. I really understand it much more now.
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