Asked by anonymous
prove |uxv| = |u||v|sin theta
Answers
Answered by
oobleck
usually |uxv| is defined to be the area of the parallelogram whose sides are u and v.
If you draw such a parallelogram, the altitude to u is |v| sinθ
since A = bh, that is |u||v| sinθ
There are other proofs online, depending on which definition of uxv you start with.
If you draw such a parallelogram, the altitude to u is |v| sinθ
since A = bh, that is |u||v| sinθ
There are other proofs online, depending on which definition of uxv you start with.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.