Prove that 1/sin theta-tan theta and - 1/cos theta = 1/cos theta and + 1/sec theta+tan theta

Answer 1

The way you typed it

1/sinØ-tanØ + - 1/cosØ = 1/cosØ + 1/secØ + tanØ

the statement is false and thus cannot be proven true

Please ret-type it using brackets.
e.g.
did you mean
1/(sinØ-tanØ) + (- 1/cosØ) = 1/cosØ + 1/(secØ + tanØ) ?

Answer 2

i mean to say
1/sinØ-tanØ - 1/cosØ = 1/cosØ + 1/secØ + tanØ

Answer 3

In that case the statement is false
try Ø=30°
Left Side = 1/sin30 - tan30 - 1/cos30
= 2-1/√3 - 2/√3 = appr. .2679
Right Side = 1/cos30 + 1/sec30 + tan30 = appr. 2.598

You will need brackets to tell us how the equation is.
You must put brackets around the denominator

e.g. 1/sinØ+ tanØ ≠ 1/(sinØ+tanØ)

Answer 4

the answer is = 2/cosØ , L.H.S = R.H.D