Ask a New Question

Question

Prove that 1+tan(Theta)/1-tan(Theta) = sec^2(Theta)+2tan(Theta)/1-tan^2(Theta)

If you explain, that would be great (:
13 years ago

Answers

Steve
(1+tan)/(1-tan)

multiply top and bottom by 1+tan

(1+tan)^2 / (1-tan)(1+tan)

(1 + 2tan + tan^2)/(1-tan^2)

now, since sec^2 = 1+tan^2,

(sec^2 + 2tan)/(1-tan^2)
13 years ago

Related Questions

prove the identity: (tan theta)/(csc theta) + 1/(sec theta)= sec theta Prove that tan(theta)tan(60+theta)=tan3theta prove that tan(45+theta)+tan(45-theta)=2sec2theta prove that: sin theta -cos theta +1/sin theta +cos theta-1=1/sec theta -tan theta prove tan (theta/2)= (sin(theta))/(1+cos(theta))for theta in quadrant 1 by providing the calculation... Prove sin theta ( sec theta+ csc theta)= tan theta+1 Prove that sec theta + tan theta = tan (45° + theta/2) prove that 2 cosec 4 theta sec 2 theta=(1-tantheta/1+tantheta)cosec2theta prove |uxv| = |u||v|sin theta prove that cos^2 theta +tan theta cosec theta=cos theta
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use