Asked by Harriet

A metal x with relative atomic mass 56 forms an oxide with formula x2O3 . How many grams of metal will combine with 10g of oxygen?(o= 16)

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Answered by Anonymous
?X + ?O2 --- > ? X2O3 well we will need at least 6 O atoms
4 X + 3 O2 ---> 2 X2 O3
so 10 g O
mols O * 16 grams/ mol = 10 grams
that is 10/16 = 0.625 mols O
every mol of X2O3 contains 3 mols of O
so we have 0.625/3 = 0.298 mols of X2O3 or 0.596 mols of X
.596 * 56 = ?

Answered by Oko
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Answered by Anonymous
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Answered by tamuno
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4
Answered by Morgan T Hart
23.3
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