Asked by Mary
The relative atomic mass of natural lithium is 6.95 it consist of two isotopes of relative masses 6.02 7.02 calculate the natural abundance of the isotopes
Answers
Answered by
Arora
Fractional abundance of Isotope 1 = x
Fractional abundance of Isotope 2 = (1 - x)
The average mass in this case is 6.95
=> (Mass 1)*(Abundance 1) + (Mass 2)*(Abundance 2) = 6.95
=> 6.02*x + 7.02*(1-x) = 6.95
=> 7.02 - 6.95 = x
=> x = 0.07
=> 1- x = 0.93
Hence, Isotope 1 is 7% while Isotope 2 is 93%
Fractional abundance of Isotope 2 = (1 - x)
The average mass in this case is 6.95
=> (Mass 1)*(Abundance 1) + (Mass 2)*(Abundance 2) = 6.95
=> 6.02*x + 7.02*(1-x) = 6.95
=> 7.02 - 6.95 = x
=> x = 0.07
=> 1- x = 0.93
Hence, Isotope 1 is 7% while Isotope 2 is 93%
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