Asked by Bobbie
How would I solve this by completing the square?
x^2+ 8x – 2 = 0
x^2+ 8x – 2 = 0
Answers
Answered by
Hi
Wait a sec
Answered by
Eric
You could use mathpapa.com
Answered by
Bobbie
I'll give that a try.
Answered by
Bobbie
Eric, it didn't show me the steps to get the answer.
Answered by
oobleck
x^2 + 8x - 2
8/2 = 4, and 4^2 = 16, so add and subtract 16
x^2 + 8x + 16 - 2 - 16
(x+4)^2 - 18
8/2 = 4, and 4^2 = 16, so add and subtract 16
x^2 + 8x + 16 - 2 - 16
(x+4)^2 - 18
Answered by
Eric
Hmmm, a relatively hard question but I can solve it
x^2+8x=2,
If b=8, then we need to add (b/2)^2=16,
So x^2+8x+16=18,
(X+4)^2=+- sqrt18,
x=-4(3sqrt2)
P.S sorry about the late response.
x^2+8x=2,
If b=8, then we need to add (b/2)^2=16,
So x^2+8x+16=18,
(X+4)^2=+- sqrt18,
x=-4(3sqrt2)
P.S sorry about the late response.
Answered by
Bobbie
Thanks Eric!
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