Asked by Lucina
Solve 0 = 3x^2 + 5x -1 by completing the square. Express your answer as exact roots.
3(x^2 + 5/3 + 25/36) = -1
(x+ 5/6)^2 = 37/36
sq root( x + 5/6)^2 = sq root (37/36)
x + 5/6 = +- sq root 37/6
x = -5/6 +- square root 37 /6 <---
(Sorry for the work being so messy! It'd be much neater if I could type the symbol for square root)
3(x^2 + 5/3 + 25/36) = -1
(x+ 5/6)^2 = 37/36
sq root( x + 5/6)^2 = sq root (37/36)
x + 5/6 = +- sq root 37/6
x = -5/6 +- square root 37 /6 <---
(Sorry for the work being so messy! It'd be much neater if I could type the symbol for square root)
Answers
Answered by
Reiny
You are correct,
but write it as
x = (-5 ± √37)/6
I use a Mac and to get √7 I press "option v"
but write it as
x = (-5 ± √37)/6
I use a Mac and to get √7 I press "option v"
Answered by
Lucina
Thanks! But could you please explain why we take off one of the 6's?
I use a Windows PC and cant find the command for square roots
I use a Windows PC and cant find the command for square roots
Answered by
Damon
Because she used parentheses.
Answered by
Lucina
Thank you
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