Asked by Skiolwe
Can someone tell me how to solve this? I’m having trouble with equations:
“A sample contains 20 kg of radioactive material. The decay constant of the material is 0.179 per second. If the amount of time that has passed is 300 seconds, how much of the original material is still radioactive? Show all work.”
“A sample contains 20 kg of radioactive material. The decay constant of the material is 0.179 per second. If the amount of time that has passed is 300 seconds, how much of the original material is still radioactive? Show all work.”
Answers
Answered by
oobleck
For decay constant λ, the amount left is
y = N*e^(-kt)
20e^(-0.179*300) = 9.5*10^-23 kg
y = N*e^(-kt)
20e^(-0.179*300) = 9.5*10^-23 kg
Answered by
Student
can you please break it down a little further. Like, explain it to me as if I were a person whose never done it before....
Answered by
Student
@oobleck
Answered by
Anonymous
(20 kg) x e ^{- 0.179 \times 300}
= (20 kg ) x e ^{- 53.7}
= (20 kg) x (4.77 x 10-24)
= 9.54 x 10-23 kg
= (20 kg ) x e ^{- 53.7}
= (20 kg) x (4.77 x 10-24)
= 9.54 x 10-23 kg
Answered by
Mr. Hojman
Dont cheat.. rats
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