Question
I really need your help in solving this problem. I appreciate your time and efforts. Have a terrific day :) Here is the question:
For each expression, perform the indicated operations and simplify, if possible. Solve each equation and check the result.
Two part question:
A. u^2 +1/u^2-u -u/u-1
B. u^2 +1/u^2-u -u/u-1 = 1/u
For each expression, perform the indicated operations and simplify, if possible. Solve each equation and check the result.
Two part question:
A. u^2 +1/u^2-u -u/u-1
B. u^2 +1/u^2-u -u/u-1 = 1/u
Answers
I assume you mean
(u^2+1)/(u^2-u) - u/(u-1)
Clearly the LCD is u(u-1)
(u^2+1 - u(u+1)) / u(u-1)
(-u+1) / u(u-1)
Now put both sides over the LCD, throw out u=0,1 and set the numerators equal.
Then solve for u.
What do you get?
(u^2+1)/(u^2-u) - u/(u-1)
Clearly the LCD is u(u-1)
(u^2+1 - u(u+1)) / u(u-1)
(-u+1) / u(u-1)
Now put both sides over the LCD, throw out u=0,1 and set the numerators equal.
Then solve for u.
What do you get?
I am not sure but I will write all of this down. Thank you Steve.
Yours,
JAY
Yours,
JAY
I'm sure that by now you have figured out that I made an error:
(u^2+1 - u^2) / u(u-1)
1 / u(u-1)
Now set that equal to 1/u
1 / u(u-1) = 1/u
1 = u-1
u = 2
check:
5/2 - 2/1 = 1/2
(u^2+1 - u^2) / u(u-1)
1 / u(u-1)
Now set that equal to 1/u
1 / u(u-1) = 1/u
1 = u-1
u = 2
check:
5/2 - 2/1 = 1/2
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