work = force * distance
= √(3.16^2 + 4.21^2)N * (6.52-2.81)m = ____ J
the force F = (3.16 N)i + (4.21 N)j acts on a particle as it moves along the x axis from x = 2.81 m to x = 6.52 m.
what is the work done, in joules, by the force?
1 answer