Asked by anonymous
the force F = (3.16 N)i + (4.21 N)j acts on a particle as it moves along the x axis from x = 2.81 m to x = 6.52 m.
what is the work done, in joules, by the force?
what is the work done, in joules, by the force?
Answers
Answered by
oobleck
work = force * distance
= √(3.16^2 + 4.21^2)N * (6.52-2.81)m = ____ J
= √(3.16^2 + 4.21^2)N * (6.52-2.81)m = ____ J
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.