Asked by Abbie

What force is necessary to keep a 2.00x10^3 car moving up a 15.0 degree incline at a constant velocity? (Mu=.200)
Answered by bobpursley
the force is equal to the gravity component down the hill, plus friction.

friction: mg*mu*CosTheta
gravity: mg*sinTheta

add those.
Answered by Stephen
5072.9659
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