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Asked by Amy

Suppose angle A is in quadrant I, and sinA = 2/5. Find the exact value of sin(360 deg - A).
4 years ago

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Answered by oobleck
for any A, sin(360-A) = -sinA
4 years ago
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Suppose angle A is in quadrant I, and sinA = 2/5. Find the exact value of sin(360 deg - A).

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