Asked by Johnny
Let be an angle in quadrant II such that sec(theta) -4/3 .
Find the exact values of cot (theta) and sin (theta).
Find the exact values of cot (theta) and sin (theta).
Answers
Answered by
Anonymous
cos(theta)=1/sec(theta)= -3/4
sin(theta)+ OR - sqroot[1-cos^2(theta)]
Sine is positive in Quadrant II so:
sin(theta)=sqroot[1-(-3/4)^2]
sin(theta)=sqroot(1-9/16)
sin(theta)=sqroot(16/16-9/16)
sin(theta)=sqroot(7/16)
sin(theta = sqroot(7) / 4
cot(theta)=cos(theta)/sin(theta)
cot(theta)=(-3/4)/(sqroot(7)/4)
cot(theta)= -3/sqroot(7)
sin(theta)+ OR - sqroot[1-cos^2(theta)]
Sine is positive in Quadrant II so:
sin(theta)=sqroot[1-(-3/4)^2]
sin(theta)=sqroot(1-9/16)
sin(theta)=sqroot(16/16-9/16)
sin(theta)=sqroot(7/16)
sin(theta = sqroot(7) / 4
cot(theta)=cos(theta)/sin(theta)
cot(theta)=(-3/4)/(sqroot(7)/4)
cot(theta)= -3/sqroot(7)
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