Question
suppose that the angle theta is in the second quadrant, and that sin(theta)=1/3. Find exact values for cos (theta) and csc (theta)
Answers
bobpursley
csc=1/sin=3
cos^2 Theta+sin^2 Theta=1
cos^2=1-sin^2=8/9
cosTheta=sqrt(4*2/9)=2/3 sqrt2 and in the second quadrant, it is negative (minus)
cos^2 Theta+sin^2 Theta=1
cos^2=1-sin^2=8/9
cosTheta=sqrt(4*2/9)=2/3 sqrt2 and in the second quadrant, it is negative (minus)