Asked by Lily
A 60-kg box is pushed across the top of a smooth horizontal table. A horizontal force, pointing East, with a magnitude of 360 N is needed to accelerate the box at a rate of 6 m/s ^ 2 in the East direction. What is the force of friction, both magnitude and direction , acting on the box ?
Answers
Answered by
R_scott
f = m a
360 N = 60 kg * 6 m/s^2
so there is no friction force
"trick" question?
360 N = 60 kg * 6 m/s^2
so there is no friction force
"trick" question?
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