Asked by Yarielis
A 115.0 kg box is pushed by a horizontal force F at constant speed up a frictionless ramp which makes an angle of 46.0 deg with the horizontal. Find the magnitude of the applied force F. what is the magnitude of the normal force between the ramp and the box?
Answers
Answered by
Henry
m*g = 115 * 9.8 = 1127 N. = Wt of box.
Fp = 1127*sin46 = 810.7 N. = Force
parallel to the ramp.
F-Fp = m*a
F - 810.7 = m*0 = 0
F = 810.7 N.
Fn = 1127*cos46 = 782.9 N. = Normal
force.
Fp = 1127*sin46 = 810.7 N. = Force
parallel to the ramp.
F-Fp = m*a
F - 810.7 = m*0 = 0
F = 810.7 N.
Fn = 1127*cos46 = 782.9 N. = Normal
force.
Answered by
Anonymous
That's wrong
Answered by
Henry
Correction:
F*cosA-Fp = m*a
F*cos46-810.7 = m*0 = 0
F*cos46 = 810.7
F = 1167 N.
F*cosA-Fp = m*a
F*cos46-810.7 = m*0 = 0
F*cos46 = 810.7
F = 1167 N.
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