m*g = 115 * 9.8 = 1127 N. = Wt of box.
Fp = 1127*sin46 = 810.7 N. = Force
parallel to the ramp.
F-Fp = m*a
F - 810.7 = m*0 = 0
F = 810.7 N.
Fn = 1127*cos46 = 782.9 N. = Normal
force.
A 115.0 kg box is pushed by a horizontal force F at constant speed up a frictionless ramp which makes an angle of 46.0 deg with the horizontal. Find the magnitude of the applied force F. what is the magnitude of the normal force between the ramp and the box?
3 answers
That's wrong
Correction:
F*cosA-Fp = m*a
F*cos46-810.7 = m*0 = 0
F*cos46 = 810.7
F = 1167 N.
F*cosA-Fp = m*a
F*cos46-810.7 = m*0 = 0
F*cos46 = 810.7
F = 1167 N.
1 answer