Question
A 660 kg car is being pushed along a flat parking lot at a constant speed of 1.52 m/s. The coefficient of friction between the road and the car is 0.31. What force is being used to push the car?
Answers
Henry
Wc=M * g = 660kg * 9.8N/kg = 6468 N. =
Weight of the car.
Fex - Ff = m*a
Fex - 0.31*6468 = m*0 = 0
Fex = 2005 N. = Force exerted.
Weight of the car.
Fex - Ff = m*a
Fex - 0.31*6468 = m*0 = 0
Fex = 2005 N. = Force exerted.