I suspect a typo, due to the carelessness with parentheses. This "identity" reduces to
sin^2θ = cos^2θ
Prove this
Cot²(90-theta) /tan² theta-1 + cosec²theta/sec²theta-cosec²theta=
1/sin²theta - cos²theta
1 answer
Cot²(90-theta) /tan² theta-1 + cosec²theta/sec²theta-cosec²theta=
1/sin²theta - cos²theta
1 answer
1 answer
1 answer
4 answers
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