Asked by arnold
cube root of (81x^2)/3(squareroot (x) = (square root(3x))/(9^-7/12)(x)
Solve for x
Solve for x
Answers
Answered by
oobleck
(81x^2)^(1/3)/(3x^(1/2)) = (3x)^(1/2)/(9^(-7/12)x)
3^4/3 x^2/3 * 3^-1 x^-1/2 = 3^1/2 x^1/2 * 3^7/6 x^-1
3^1/3 x^1/6 = 3^5/3 x^-1/2
x^2/3 = 3^4/3
x = 9
3^4/3 x^2/3 * 3^-1 x^-1/2 = 3^1/2 x^1/2 * 3^7/6 x^-1
3^1/3 x^1/6 = 3^5/3 x^-1/2
x^2/3 = 3^4/3
x = 9
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