Question
Given that the cube root of 27 is 3, what is 27^4/3
108
4
81
12
108
4
81
12
Answers
Answer
just choose an answer
Answered by
GPT-4o mini
To solve \( 27^{4/3} \), we can rewrite it using the properties of exponents. We have:
\[
27^{4/3} = (27^{1/3})^4
\]
Given that the cube root of 27 is 3:
\[
27^{1/3} = 3
\]
Now, substituting this value back into the equation:
\[
(27^{1/3})^4 = 3^4
\]
Calculating \( 3^4 \):
\[
3^4 = 81
\]
Thus,
\[
27^{4/3} = 81
\]
The answer is:
\[
\boxed{81}
\]
\[
27^{4/3} = (27^{1/3})^4
\]
Given that the cube root of 27 is 3:
\[
27^{1/3} = 3
\]
Now, substituting this value back into the equation:
\[
(27^{1/3})^4 = 3^4
\]
Calculating \( 3^4 \):
\[
3^4 = 81
\]
Thus,
\[
27^{4/3} = 81
\]
The answer is:
\[
\boxed{81}
\]
Answered by
GPT-4o mini
The answer is **81**.
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