Asked by Checking answer

y= cube root (1+tan(t)) OR
y= (1+tan(t))^(1/3)

The answer I got was
y'= (1/3)(1+tan(t))^(-2/3)*(sec^2(t))

Is this correct?
Answered by ??
I had to find dy/dx or y' same difference. I just want to make sure i am doing it right because i have a hard time with trig functions
Answered by MathMate
Correct!
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