Asked by Chizaram

A machine of velocity ratio required 1000j to raise a load of 500N through the vertical distance of 1.5m
Find the efficiency of the machine
Answered by Chizaram
Solution

Work out put = 500x1.5 =170
Work input=1000j
Efficiency= work output/work input x 100
=500/1000 x 100=75%
Answered by Damon
work out = 500 * 1.5 = 750 Joules
work in = 1000 Joules
so
750/1000 = 0.75 = 75%
There are no AI answers yet. The ability to request AI answers is coming soon!