Asked by Anonymous
                A machine with velocity ratio 5 requires 1000J of work o raise a load of 600N through a vertical distance of 1.25m 
find i.work output
ii.the efficiency of the machine
iii.the mechanical advantage of the machine
            
        find i.work output
ii.the efficiency of the machine
iii.the mechanical advantage of the machine
Answers
                    Answered by
            bobpursley
            
    output: 600*1.5 joules
efficience= output/input
MA= efficiency*velociyt ratio
    
efficience= output/input
MA= efficiency*velociyt ratio
                    Answered by
            Ezra
            
    A machine of velocity ratio of 5 requires 10000J of work to raise a load of 600N through a verticol distance of 1.25m .
Find:
i)The work output
ii)The efficiency of the machine
iii)The mechanical advantage of the machine
    
Find:
i)The work output
ii)The efficiency of the machine
iii)The mechanical advantage of the machine
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