Asked by Anonymous

A machine with velocity ratio 5 requires 1000J of work o raise a load of 600N through a vertical distance of 1.25m
find i.work output
ii.the efficiency of the machine
iii.the mechanical advantage of the machine
Answered by bobpursley
output: 600*1.5 joules
efficience= output/input
MA= efficiency*velociyt ratio
Answered by Ezra
A machine of velocity ratio of 5 requires 10000J of work to raise a load of 600N through a verticol distance of 1.25m .
Find:
i)The work output
ii)The efficiency of the machine
iii)The mechanical advantage of the machine
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