Question

In the reaction between aqueous solutions of lead(II) chlorate and sodium iodide, which ions become spectator ions?

a) Pb2+

b) ClO3-

c) Na+

d) I-

Answer 1

Pb(ClO3)2(aq) + 2NaI(aq) ==> PbI2(s) + 2NaClO3(aq)
Notice which is the solid ppt. The net ionic equation for PbI2 with the ions leading up to the ppt is Pb^2+(aq) 2I^-(aq) ==> PbI2(s)
The other ions are the spectator ions.