Asked by Sarah
The reaction of aqueous sodium bromide and aqueous lead(II) nitrate is represented by the balanced net ionic equation.
2Br-(aq) + Pb2+(aq) → PbBr2(s)
Give the balanced ionic equation for the reaction. Include the states.
2Br-(aq) + Pb2+(aq) → PbBr2(s)
Give the balanced ionic equation for the reaction. Include the states.
Answers
Answered by
DrBob222
This question is asking for the reverse of your previous posts; that is, the question wants you to take the net ionic equation given and make the molecular equation, then the ionic equation from that.
2NaBr(aq) + Pb(NO3)2(aq) ==> PbBr2(s) + 2NaNO3(aq), then
2Na^+(aq) + 2Br^-(aq) + Pb^+2(aq) + 2NO3^-(aq) ==> PbBr2(s) + 2Na^+2(aq) + 2NO3^-(aq)
Check my work to make sure all of the charges and (aq) marks are showing correctly.
2NaBr(aq) + Pb(NO3)2(aq) ==> PbBr2(s) + 2NaNO3(aq), then
2Na^+(aq) + 2Br^-(aq) + Pb^+2(aq) + 2NO3^-(aq) ==> PbBr2(s) + 2Na^+2(aq) + 2NO3^-(aq)
Check my work to make sure all of the charges and (aq) marks are showing correctly.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.