Asked by Jake Kubehl
A)You drop a stone from a position of rest.
How far will it fall vertically in the first 3 s?
The acceleration of gravity is 9.8 m/s
Answer in units of m
B)If you instead toss it horizontally at 1.8 m/s,
how far will it fall vertically in the first 3 s?
How far will it fall vertically in the first 3 s?
The acceleration of gravity is 9.8 m/s
Answer in units of m
B)If you instead toss it horizontally at 1.8 m/s,
how far will it fall vertically in the first 3 s?
Answers
Answered by
Damon
We already discussed the fact that the vertical motion can be solved separately from the constant horizontal speed motion
THERE IS NO DIFFERENCE between A and B
vertical problem:
a = -g = -9.81 m/s^2
v = Vi + a t = -9.81 t = -9.81*3 = - 39.4 m/s
h = Hi + Vi t - 4.9 t^2
h = Hi + 0 - 4.9* 9 = Hi - 44.1
so
Hi initial height - h height at 3 seconds = distance fallen = 44.1 meters
THERE IS NO DIFFERENCE between A and B
vertical problem:
a = -g = -9.81 m/s^2
v = Vi + a t = -9.81 t = -9.81*3 = - 39.4 m/s
h = Hi + Vi t - 4.9 t^2
h = Hi + 0 - 4.9* 9 = Hi - 44.1
so
Hi initial height - h height at 3 seconds = distance fallen = 44.1 meters
Answered by
Some guy
Damon, your answer is wrong
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