Asked by tommy
If you drop a stone into a well that is d = 128.0 m deep, how soon after you drop the stone will you hear it hit the bottom of the well?
Answers
Answered by
Damon
g = acceleration = -9.8 m^s^2
z = height = zo - Vo t - (1/2)(9.8)t^2
z = final height = -128
zo = initial height = 0
Vo = starting velocity = 0
so
-128 = -4.9 t^2
t^2 = 128/4.9
t = 5.11 seconds
z = height = zo - Vo t - (1/2)(9.8)t^2
z = final height = -128
zo = initial height = 0
Vo = starting velocity = 0
so
-128 = -4.9 t^2
t^2 = 128/4.9
t = 5.11 seconds
Answered by
Dylan
Since the sound still needs to travel back up the well, it will actually take longer than 5.11 seconds.
v=d/t
343=128/t
t=0.37
5.11+0.37=5.48 seconds.
v=d/t
343=128/t
t=0.37
5.11+0.37=5.48 seconds.
Answered by
Bambii
where did the 343 come from?
Answered by
Alek
343 meters per second is the speed of sound.
Answered by
Alek
Well actually its the speed of sound in air at 20 degrees C
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