Asked by Adikanda
A stone drop down from a tower at a hight of 20m.At the same time another stone thrown vertically upward in a velocity of 50 m/s .In what time and what hight the two stones are meet with each other.
Answers
Answered by
oobleck
just set their heights equal:
20 - 4.9t^2 = 50t - 4.9t^2
20 = 50t
...
20 - 4.9t^2 = 50t - 4.9t^2
20 = 50t
...
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