Asked by Anonymous
A tower is 88m high a stone is thrown vertically upward from the top of the tower with a velocity 2m/s The stone reach the ground after how many seconds?
Answers
Answered by
oobleck
using your basic equation of motion, the height h at time t is
h(t) = 88 + 2t - 4.9t^2
so, just find t when h=0
h(t) = 88 + 2t - 4.9t^2
so, just find t when h=0
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