Question

How to find angle between 0°and 360° whose sine is 0.9962
sin 85° = 0.9962

In the second quadrant, the values for sin are positive.

You can use formula:

sin ( 180° - θ ) = sin θ

sin ( 180° - 85° ) = sin 95° = sin 85° = 0.9962

In the third and fourth quadrants the values for sin are negative, so the only angles between 0°and 360° whose sine is 0.9962 are:

θ = 85° and θ = 95°




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