Asked by alysia
Find the sin(Θ) of an angle in standard position if the terminal side passes through the point (4, -8).
Answers
Answered by
Reiny
recall sinØ = y/r
from the given: r^2 = 4^2 + (-8)^2 = 80
r = √80 = 4√5
since (4,-8) is in quad IV , and in IV the sine is negative,
sinØ = -8/4√5 = -2/√5
or -2√5/5
from the given: r^2 = 4^2 + (-8)^2 = 80
r = √80 = 4√5
since (4,-8) is in quad IV , and in IV the sine is negative,
sinØ = -8/4√5 = -2/√5
or -2√5/5
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