Asked by saleem abbas
find the angle between A=-5i-3j+2k and B=0i-2j-2k?
Answers
Answered by
Damon
A dot B = |A| |B| cos T
0 + 6 - 4 = sqrt(38) sqrt(8) cos T
2 = 17.44 cos T
T = cos^-1 .1147
T = 83.4 degrees
0 + 6 - 4 = sqrt(38) sqrt(8) cos T
2 = 17.44 cos T
T = cos^-1 .1147
T = 83.4 degrees
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