Asked by Ariana
How do you find the angle, θ, between the vectors? If needed, round your answer to the nearest tenth.
1.) u = 2i - 3j
v = i - 2j
2.) u = <3, 2>
v = <4, 0>
1.) u = 2i - 3j
v = i - 2j
2.) u = <3, 2>
v = <4, 0>
Answers
Answered by
Reiny
1.
dot product
u ∙ v = |u| |v| cosØ, where Ø is the angle between them, so
<2,-3> ∙ <1,-2> = √13 √5 cosØ
2+6 = √13√5cosØ
cosØ = 8/(√13√5) = .99227...
Ø = appr 7.1°
do #2 the same way
dot product
u ∙ v = |u| |v| cosØ, where Ø is the angle between them, so
<2,-3> ∙ <1,-2> = √13 √5 cosØ
2+6 = √13√5cosØ
cosØ = 8/(√13√5) = .99227...
Ø = appr 7.1°
do #2 the same way
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.